"tengu_post_compact_survey": false,
题号题目核心考点496下一个更大元素 I单调栈 + Map 缓存739每日温度下一个更大 + 存索引算距离503下一个更大元素 II循环数组（2 倍长度 + 取模）1019链表中的下一个更大节点链表转数组 + 模板1944队列中可以看到的人数弹栈计数 + 栈顶是否可见1475商品折扣后的最终价格右侧第一个 ≤ cur901股票价格跨度上一个更大（正序）402移掉 K 位数字单调递增栈 + k 限制853车队排序 + 时间比较（可不用栈）581最短无序连续子数组边界 + 最值扩展（非纯单调栈）
。搜狗输入法2026对此有专业解读
Stream implementations can and do ignore backpressure; and some spec-defined features explicitly break backpressure. tee(), for instance, creates two branches from a single stream. If one branch reads faster than the other, data accumulates in an internal buffer with no limit. A fast consumer can cause unbounded memory growth while the slow consumer catches up, and there's no way to configure this or opt out beyond canceling the slower branch.
"Maternity and neonatal services in England are failing too many women, babies, families and staff," said Baroness Amos, who is leading a government-commissioned review (file photo)